• pivot_root@lemmy.world
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    1 day ago

    you’d end up using modulus and move on quickly.

    But where’s the fun in that?

    There are so many better for obfuscation ways of checking for oddness!

    (a & 1) > 0
    a.toString()[a.toString().length()-1] - '1' == 0
    iseven(a)?(1==0):(1!=0)