SnokenKeekaGuard@lemmy.dbzer0.comM to Anti Meme@sopuli.xyz · 2 months agoHowwww??lemmy.dbzer0.comimagemessage-square26fedilinkarrow-up1136arrow-down15
arrow-up1131arrow-down1imageHowwww??lemmy.dbzer0.comSnokenKeekaGuard@lemmy.dbzer0.comM to Anti Meme@sopuli.xyz · 2 months agomessage-square26fedilink
minus-squareBCsven@lemmy.calinkfedilinkarrow-up25·2 months agoMaybe thee is an elegant way but X+y+w+z=360° Given X+y=w+z Therefore we can sub X+y with w+z (W+z)+(w+z)=360° 2(W+z)=360° Divide both sides by 2 W+z=360°/2 W+z=180° Straight lines are defined as having/being 180 angle
minus-squareSnokenKeekaGuard@lemmy.dbzer0.comOPMlinkfedilinkarrow-up10arrow-down1·2 months agoOh i forgot about x+y being given as w+z. Yep with that its all good. I thought you made that assumption.
minus-squareHeuristicAlgorithm9@feddit.uklinkfedilinkarrow-up3arrow-down1·2 months agoThe elegant way would be to use radians over degrees
minus-squareBCsven@lemmy.calinkfedilinkarrow-up3·2 months agoYou have to show your work in snokenkeekaguard’s class
Maybe thee is an elegant way but
X+y+w+z=360°
Given X+y=w+z
Therefore we can sub X+y with w+z
(W+z)+(w+z)=360°
2(W+z)=360°
Divide both sides by 2
W+z=360°/2
W+z=180°
Straight lines are defined as having/being 180 angle
Oh i forgot about x+y being given as w+z. Yep with that its all good. I thought you made that assumption.
The elegant way would be to use radians over degrees
You have to show your work in snokenkeekaguard’s class
Wdym?