• Gobbel2000@programming.dev
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      12 hours ago

      Okay, but even if we assumed (x=b) to be a very small equivalence relation, it should appear in the denominator position to form an equivalence quotient.

      • Crazazy [hey hi! :D]@feddit.nl
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        11 hours ago

        Oh yeah was a bit sleepy and thought you could just put arbitrary expressions in the numerator instead of just the type.

        But consider this: heterogeneous propositional equality type of types x and b under equivalence relation a, which is bound somewhere else in the aether that we can’t see in the screenshot

        Constructors of this equality type? No fucking clue but I’m sure there exist some to make the need for an equivalence relation make sense

        • Gobbel2000@programming.dev
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          9 hours ago

          You’re probably on the right track. Every hunk of symbols is probably a valid type expression in some system. Including a square root type.