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Stamets@lemmy.world to memes@lemmy.world · 3 days ago

I mean... I don't see the problem?

lemmy.world

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  • cross-posted to:
  • science_memes@mander.xyz
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I mean... I don't see the problem?

lemmy.world

Stamets@lemmy.world to memes@lemmy.world · 3 days ago
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  • cross-posted to:
  • science_memes@mander.xyz

  • Randelung@lemmy.world
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    3 days ago

    No one said right angles.

    • Mistic@lemmy.world
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      2 days ago

      Equal sides in a triangle are only possible if the corners are equal. So, 60⁰ each.

      But its height cannot be half of base because of the same Pythagorean theorem

      (1,5)²+(1,5/2)²=2,8125

      sqrt(2,8125) ≈ 1,677, which is half of a diagonal

      So, we get 4 sides that are 1,5 in a parallelogram, but diagonals are 1,5 and 3,354, as opposed to both being 1,5 as shown on the picture

      TL;DR: Won’t work because Pythagorean theorem

      • Obi@sopuli.xyz
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        2 days ago

        It’s funny how we say “because of such and such theorem” as if if some greek dude didn’t come up with his little story, the height could totally be half of base.

        • andros_rex@lemmy.world
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          2 days ago

          Babylonians had it figured it somewhat out for astronomy purposes about a thousand years before the weird bean hater.

        • bss03@infosec.pub
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          2 days ago

          Decolonialize Maths!

          We do need short names, but they don’t all have to be wyt guys. Pre-globalization, I’m sure many true maths statements were independently discovered by many people.

      • rowinxavier@lemmy.world
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        2 days ago

        Pyramid?

        • kryptonianCodeMonkey@lemmy.world
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          2 days ago

          Yes, it is possible with a 3-sided pyramid, i.e. tetrahedron. If we dont look at all 4 points as being on the same plane but 2 opposite corners being offset above or below the other two, this could totally be a tatrahedron.

          • ptu@lemm.ee
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            2 days ago

            So those two darker green symbols would represent someone shorter or taller. Totally plausible.

        • Mistic@lemmy.world
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          2 days ago

          Wdym?

          • TheButter_ItSeeps@lemmy.world
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            2 days ago

            They could each be on the vertices of a tetrahedron for all we know…

            • bss03@infosec.pub
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              2 days ago

              We do know that, with those measurements, they aren’t confined to a single (Euclidean) plane.

              • Lovable Sidekick@lemmy.world
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                2 days ago

                Exactly! I regret that I have but one upvote to give.

            • Mistic@lemmy.world
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              2 days ago

              I was thinking of plane surfaces, but if their altitudes are different, I guess it’d be possible.

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